(c^2)-(2c)=35

Solution for (c^2)-(2c)=35 equation:

Simplifying
(c2) + -1(2c) = 35
c2 + -1(2c) = 35

Remove parenthesis around (2c)
c2 + -1 * 2c = 35

Multiply -1 * 2
c2 + -2c = 35

Reorder the terms:
-2c + c2 = 35

Solving
-2c + c2 = 35

Solving for variable 'c'.

Reorder the terms:
-35 + -2c + c2 = 35 + -35

Combine like terms: 35 + -35 = 0
-35 + -2c + c2 = 0

Factor a trinomial.
(-5 + -1c)(7 + -1c) = 0

Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve:

Simplifying
-5 + -1c = 0

Solving
-5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1c = 0 + 5
-1c = 0 + 5

Combine like terms: 0 + 5 = 5
-1c = 5

Divide each side by '-1'.
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(7 + -1c)' equal to zero and attempt to solve:

Simplifying
7 + -1c = 0

Solving
7 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1c = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1c = 0 + -7
-1c = 0 + -7

Combine like terms: 0 + -7 = -7
-1c = -7

Divide each side by '-1'.
c = 7

Simplifying
c = 7
Solution
c = {-5, 7}